a stone is thrown vertically upwards with a velocity of 20m/s. Find maximum height reached by stone and total time of flight...
PLEASE ANSWER THIS QUESTION HURRILY...
BlackCell:
are u sure that the Question u asked is correct... i mean acceleration must be given..
Where's the angle ?
well i thing we don't need for angle.if acceleration or time is giVen tHen wE cAn eAsily sOlvE it bY Equation of mOtion.
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The projectile motion formulas would be applicable here .
Max ht =vi^2 sin^2 theta / 2g
And total time taken by the flight i.e: t = 2vi sin theta /g
Max ht =vi^2 sin^2 theta / 2g
And total time taken by the flight i.e: t = 2vi sin theta /g
Projectile....oh sorry noW i gEt it.thanks btw.
Thanx alot ...
Np ;)
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