Question

A stone is thrown vertically upwards with a velocity of 20m per second calculate the maximum height achieved by the stone?

Answer 1

Answer:

h = 20.387m

Explanation:

given,

initial velocity, u = 20 m/s

maximum height reached = h

final velocity after reaching h = v = 0 m/s  (as it stops at max height and start return)

acceleration = acc. due to gravity = -g (as the body is moving upwards)

by using equation of motion,  v2 - u2 = 2*a*h

0 - (20*20) = 2 * (-9.81) * h      (g = 9.81 m/s2)

400 / 19.62 = h = 20.387 m

Answer 2

Answer:20.40 metre

Explanation: use the formula H(height) =(initial velocity) ^2 /2(acceleration due to gravity)

H=u^2/2g =20*20/(2*9.8)=20.40 metre