Question

a stone is thrown vertically upwards with a velocity of 40^-1 and returns back takiing g =10m^-2 calculate the maxium the height reached by the object stone and total distance traveled by the stone​

Answer 1

Explanation:

GIVEN THAT

INITIAL VELOCITY= 40m/s.

TO FIND MAXIMUM HEIGHT

H= U²/2G

SO H= 40²/20

H= 1600/20

Hmax= 80metre

TOTAL DISTANCE TRAVELLED = 2×Hmax

TOTAL DISTANCE TRAVELLED

2× 80 = 160 METRE

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