a stone is thrown vertically upwards with a velocity of 40 m/s
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u = 40 m/s
As the stone is thrown upward the acceleration due to gravity is to be taken negative.
g = - 10 m/s2
v2 - u2 = 2as
For free fall we can write this equation as,
v2 - u2 =2gh
As the stone reaches the maximum height its final velocity v =0
Thus,
0 - (40)2 = 2× (-10) × h
- 1600 = -20 × h
h = 80 m
So, the maximum height to which the stone can reach is 80 m.
The total distance covered by the stone = 80 + 80 = 160 m
And as thE stone comes back to its initial position the displacement of the stone = 0
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