Question

A stone is thrown vertically upwards with a velocity of 40 m/s and returns to the thrower after few seconds.
Calculate
a) The maximum height attained by the stone.
b) The total time taken by the stone to return to the thrower. (Take g= 10 m/s2 )​

Answer 1

Answer:

take a as g,

u=40m/s

v=0m/s

a) the maximum height attained by the stone, h

Therefore,

v^2−u^2=2gs

0^2−40^2=2(−10)h

h=(40×40)/20

h=80m

b) The total time taken by the stone to return to the thrower

v=u+gt

0=40+10t

40=10t

t=40/10

t=4s

I hope this helps you