Question

A stone is thrown vertically upwards with an initial velocity of 49 m/s from the top of a tower and reaches the ground in 12 seconds. Find the height of the tower. ​

Answer 1

Answer:

Explanation:

u=49m/S

t=12s

v=0

v=u+at

0=49+a(12)

0-49=a(12)

-49/12=a

4.0833=a

V2-u2=2as

0-2401=2×4.0833×S

-2401/8.166=s

-294.00024=s

Answer 2

Answer:

height of the tower = 117.6 m

Explanation:

u = 49 m/s

a = - 9.8 m/sq-sec

t = 12 s

net displacement,

s = ut + (1/2) a t^2

= 49×12 - (1/2) 9.8 × 12×12

= 49×12 (1 - 1.2)

= - 49 × 12 × 0.2

= - 117.6 m

so, height of the tower = 117.6 m