A stone is thrown vertically upwards with an initial velocity of 40 m/s. Find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?
Answers
Answer:
The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.
Explanation:
Given that,
Final velocity v = 0
Initial velocity u = 40m/s
We know that,
Using equation of motion
v
²=u²+2gh
=>0-40²=2×10×h
The maximum height is
h=80m
The stone will reach at the top and will come down
Therefore, the total distance will be
s=h1+h2
=>s=80m+80m=160m
The net displacement is
D=h1-h2
=>D=80m-80m=0
Hence, The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.
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Answer:
Maximum Height : 80 m
Total Distance : 160 m
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