A stone is thrown vertically upwards with an initial velocity and is caught back. By taking g=10m/s find the maximum height reached by the stone. What is the displacement and the total distance covered by the stone.
Answers
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Given:
A stone is thrown vertically upwards with an initial velocity and is caught back. By taking g=10m/s find the maximum height reached by the stone.
To find:
What is the displacement and the total distance covered by the stone.
Solution:
From the given information, we have the data as follows.
A stone is thrown vertically upwards with an initial velocity and is caught back. By taking g=10m/s find the maximum height reached by the stone.
The formula that is used to find the height is given as follows.
v² - u² = 2gh
v is the final velocity
u is the initial velocity
h is the height
Substitute the values in the above equations.
0² - 40² = 2 × -10 × h
h = 1600/(2 × 10)
h = 80 m
Therefore, the distance covered by the stone is 80 m.
The displacement will be zero, as the stone hits back the ground.