Question

a stone is thrown vertically upwards with an initial velocity of 30m/s and acceleration of 10m/s square . find the maximum height reached by the stone . what is the net displacement and total distance covered by the stone when it reaches back the ground


pls answer it fast

Answer 1

height is 45 m and dispacement is zero and distance is 90m and formula is vsquare-usquare=2ah

Answer 2

As object is projected upwards a=-10m/s square
Then use acceleration formula to get time
Than by formula:
s(distance)=ut+half at square