Question

a stone is thrown vertically upwards with an intial velocity of 40m/s take g to be 10m/s^2 find the maximum height reached by the stone and the time taken to reach the highest point​

Answer 1

Answer:

The maximum height reached by the stone is 80 m.

Time taken to reach the highest point is 4 s.

Explanation:

The initial velocity of the stone, u = 40 m/s

At maximum height, final velocity, v = 0 m/s

The acceleration due to gravity acting on the stone, g = -10 m/s²

The value of g is negative as the stone is moving up against the direction of gravity.

The maximum height (S) reached by the stone is found using the 3rd equation of motion.

v² - u² = 2gS

⇒ S = (v² - u²) / 2g

       = (0² - 40²) / (2 × -10)

       = -1600 / -20

   S = 80 m

The time taken to reach the maximum height can be found using the 1st equation of motion.

v = u + gt

⇒ t = (v - u) / g

   t = (0-40) / -10

   t = 4 s