Question

A stone is thrown vertically upwards with initial velocity 5m/s .on what height it will stop(g=10.m/s^2

Answer 1

Answer:

It will stop at height = 1.25 meter

Step by Step Explanation :

Given that,

A stone is thrown upward vertically with initial velocity 5 m/s

Here,

Initial velocity of the body = 5 m/s

let the maximum height that the ball can attain be h

now at its maximum height body will at rest

so,

its final velocity will zero

now we have,

Initial velocity(u) = 5 m/s

final velocity(v) = 0 m/s

gravitational acceleration(g) = -10 m/s

[acceleration against the gravitational force]

now,

by the gravitational equation of motion,

v² = u² + 2gh

putting the values,

0 = 5² + 2(-10)h

-20h + 25 = 0

-20h = -25

h = 25/20

h = 1.25 m

so,

It will stop at height = 1.25 meter

_______________

NOTE :

Formulas:

For upward movement

time to reach maximum height(t)

t = u/g

time to reach its initial position (T)

T = 2u/g

For downward movement

speed of body in hitting ground(v)

v = u²/2g

Height (H)

H = ½gt²

Answer 2

To find the height attained,

v2 = u2 + 2as

s = Height attained = (v2 - u2)/2a = (0 - 25)/(2 x -10) = 1.25 .

a is negative since it's direction is opposite to the direction of motion.

t = (v - u)/a = -5/-10 = 0.5 s.