A stone is thrown vertically upwards, with initial velocity of 48 m/ s -1. Find the maximum height to which it rises. And the total time taken to return to earth.
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1. By third equation of motion
v^2=u^2+2as
0=48×48-20s ( at maximum height v is zero)
s=48×48/20
s=115.2 m
From first equation of motion
v=u+at
0=48-10t
t= 4.8 s
Time ascent =Time of descent
Total time to reach ground =Time of ascent + Time of descent
Total time =4.8+4.8 = 9.6 s
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