Question

A stone is thrown vertically upwards with velocity of 4.9ms calculate 1.the maximum height reached 2.the time taken to reach the maximum height 3.the velocity with which it retune of the ground and

Answer 1

Explanation:

given , initial velocity = 4.9 m/s upward

let g = 9.8 m/s²

at max height final velocity (v) = 0

(1) max height reached (H) = u²/2g

(4.9×4.9) /( 2×9.8) = 1.225 m= 122.5 cm

(2) time taken to reach max height

(t) = u/g = 4.9/9.8= 0.5 second

(3) velocity at the time to reach the ground

= initial velocity= 4.9 m/sec