Question

A stone is thrown vertically upwords with a velocity of 40 m /s find its position after 5 seconds

Answer 1

Answer:

80 m

Explanation:

Given :

Initial velocity u = 40 m / sec

At top final velocity v = 0 m / sec

Time t = 5 sec

Using g = 10 m / sec²

We are asked to find height / position :

Using third equation of motion :

v² = u² + 2 g h

= > h = ( v² - u² ) / 2 g

Putting values here we get :

= > h = ( 0² - 40² ) / 2 × ( - 10 ) m

= > h = - 1600 / - 20 m

= > h = 160 / 2 m

= > h = 80 m

Therefore , required position is 80 m.