Question

A stone is thrown vertically with a velocity of 5m/s. find time required to go up and as well as come down upto a point at which it is thrown upward

Answer 1

Explanation:

Given, initial velocity, u=5ms−1

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion. 

∴a=−10ms−2

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v2−u2=2as, we have

s=v2−u2/2a

=(0)2−(5)2/2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s

Answer 2

Answer:

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Explanation:

Given, initial velocity, u=5ms

−1

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.

∴a=−10ms

−2

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v

2

−u

2

=2as, we have

s=v

2

−u

2

/2a

=(0)

2

−(5)

2

/2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s