Question

A stone is thrown vertically with an initial velocity of 30m/s.Find the maxmimum height reached by the body.(g=10m/s^2​

Answer 1

Answer:

45 m

Explanation:

Apply the formula:

V^2-u^2=2as

Here v=0 because the body reaches max. Height

Then u^2=900 , a=g=10 m/s^2

Substitute u will get the answer

Hope it will help you :)