Question

A stone is thrown verticly up from
a bridge with a initial velocity 4.9m/s it strikes
the water below the bridge after two seconds.
What is the hight of the bridge above water
leavel​

Answer 1

Answer:

9.8 m

Explanation:

Time taken for stone to reach same point

T = 2u/g

= (2 × 4.9 m/s) / (9.8 m/s²)

= 1 s

Further time taken for stone to fall

t = 2 s - 1 s

= 1 s

Height of bridge

H = ut + 0.5at²

= (4.9 m/s × 1 s) + (0.5 × 9.8 m/s² × (1 s)²)

= 4.9 m + 4.9 m

= 9.8 m