Physics, asked by gkGeetakumari4890, 8 months ago

A stone is thrown with an initial speed of 4.9 m/S from a bridge in vertically upward direction. If falls down in Water after 2 seconds. The height of the bridge is?

Answers

Answered by jumaanjunaid
5

Answer:

9.8 metres.

Explanation:

Here, I want you to understand that the height of the bridge is actually the distance covered by the stone because you threw it upwards.

Also, we know that Speed=distance/time.

In this question, we have to calculate 'distance'. Speed and time are given.

So, the equation will look like this- 4.9m/s=distance/2 secs.

= 4.9m/s × 2 secs = distance.

= distance =9.8 metres.

Therefore, height of the bridge= 9.8 metres.

Hope it helps :)

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