A stone is thrown with an initial speed of 4.9 ms
from a bridge in vertically downward direction. It
falls down in water after 1 second. Find the height
of bridge.
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Answer:
.nitial velocity of the stone u=−4.9m/s (upwards)
Acceleration of the stone g=9.8m/s
2
(downwards)
Time taken by the stone to fall down in water t=2 s
Height of the bridge H=ut+
2
1
gt
2
(Taking downward direction to be positive)
∴ H=(−4.9)(2)+
2
1
(9.8)(2)
2
=9.8 m
Step-by-step explanation:
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