A stone is thrown with horizontal velocity 4 m/s from 100 m high cliff. The radius of trajectory of stone after 0.3s is 25/n. Find n =……
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this is example ok
The initial velocity of the stone thrown from the cliff is 5 m/s
The stone strikes the pond near the base after 4 sec.
The stone moves in upward direction initially and then after reaching a maximum height, it starts to come down and reaches the base of the cliff.
In overall motion of the stone, the net displacement in the opposite direction of the initial velocity.
S=ut−
2
1
at
2
Substitute the values in above expression:
S=(5×4)−
2
1
×10×4
2
S=20−80=−60 m
So, the height of the cliff is 60 m.
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