Question

A stone is tied to one end of a string and whirled in a horizontal circle of radius 1 m at 20 revolutions
per minute. Calculate the angular velocity and linear speed of the stone. Also find the centripetal
acceleration

Answer 1

Answer:

Given length of the string l= 1 m also angular velocity ω=

44

22

revolution/second.

We know linear velocity v=ω×r

Thus velocity v=

44

22

×1=0.5 m/s

And we know centripetal or radial acceleration a

c

=

r

v

2

Thus a

c

=0.25m/s

2

Answer 2

Answer:

Explanation:

Acceleration =V2 /r .

V=rw; acc =(rw)^2/r = rw^2 .

Now W=2pif =2pif =2×3.14×20/60=2.09

Acc =1* 2.09^2 =4.38