Question

a stone is tied to one end of the string 50cm long and is whirled in horizontal circle with constant speed. if stone makes 10 revolutions in 20 seconds then wat is the magnitude of acceleration of the stone...??

Answer 1

» Radius = r = 50 cm = 0.5 m

» In 20 sec revolution = 10

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» in 1 sec revolution = 10/20 = 1/2 Hz

» N = 1/2 Hz

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Now

» Angular Velocity = w = 2πn

» Angular Velocity = w = 2×3.14×0.5

» Angular Velocity = w = 3.14

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» Radial Acceleration = w²r

» Radial Acceleration = (3.14)²×0.5 m/s²

» Radial Acceleration = 4.93 m/s²

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Answer 2

Heya!
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✒Length of String ( R ) = 50cm

=> 0.5m


✒Number of Revolutions in 20 seconds = 10

✒Number of Revolutions in 1 second ( Frequency) = ½ Hz


=> Now, the Angular Velocity w ( Omega) = 2πn


=> 2 × 3.14 × 0.5


=> 3.14................| 1 |



➖▪Then , The Radial Acceleration is given by = w² × r


[( Angular Velocity )² × Radius ]



=> ( 3.14)² × 0.5


=> 4.9 ms²


✒Hence the Acceleration of the Stone is 4.9 ms^-2 ✒


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