Question

A Stone is Whirled in vertical Circle at the end of rope of length 0.5 m. Find velocity of stone at lowest position

Answer 1

Explanation:

V ≥ 5m/sec

minimum velocity at lowest point for vertical circular motion

(Vmin) = √ (5gr)

given , r= 0.5 m let g= 10m/sec²

=> vel of stone at lowest pt

≥ √(5×10×0.5) = √25 = 5 m/ sec

Answer V ≥ 5m/sec

Additional information:-

(1) min velocity at top = √gr

(2) min velocity when rope is parallel to horizontal = √3gr