Question

A stone let fall from the top of a tower tranverses a distance of 24.5m in the last second of its fall. Find the height of the tower ?​

Answer 1

Answer:

Let the total height of the tower is h and the total time is taken to reach the ground is t.

The height is given as

h=1/2 gt²

The height before last seconds is given as,

h−24.5=1/2× g(t-1)²

Solving it

t=3s

Substitute the value of t in the equation (1), we get

1/2× 9.8 ×3²

h=44.1m

Thus, the height of the tower is 44.1m

Explanation:

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