Question

A stone lying at the edge of a road falls down into a river flowing below the road.
If the stone takes 2 second to reach the river, then find:
(i) the speed with which the stone strikes the water surface.

Answer 1

Answer:

Answer

According to the question , u=0,a=10s2m​,t=1s and we have to find v,vav​ands

for finding v we use first equation of motion :v=u+at

 this gives speed with which stone strikes water , v=0+10×1=10sm​

Now,vav​=2u+v​=210​=5sm​

and for displacement we use 2nd equation of motion :s=ut+21​at2

   this gives height of road from the river as,     s=0+21​×10×12=5m

Explanation:

Answer 2

Answer:

Here is answer bro

Explanation:

According to the question , u=0,a=10s2m​,t=1s and we have to find v,vav​ands

for finding v we use first equation of motion :v=u+at

this gives speed with which stone strikes water , v=0+10×1=10sm​

Now,vav​=2u+v​=210​=5sm​

and for displacement we use 2nd equation of motion :s=ut+21​at2

  this gives height of road from the river as,     s=0+21​×10×12=5m.