Question

A stone lying at the edge of the road falls down in a river ,flowing below the road . If the stone takes 2s to reach the river.find the height of the road from the river

Answer 1

Given-

t= 2s

g=9.8m/s

u=0m/s Because the stone is at rest

To find = height (distance covered by the rock)

Answer-

using the third formula of uniformly accelerated motion =

S = ut + 1/2× at^2

=s=(0×2) + (1/2 × 9.8 × 2 ×2)

=s= 0 + (2 × 9.8)

= s = 0 + 19.6

= s = 19.6 m

Since h is total distance covered HENCE s= h

Therefore h= 19.6 m