Physics, asked by bakugan52, 1 year ago

A stone moving along a circular path moves 20 revolutions in 10 seconds.what is the angular velocity of the stone?​

Answers

Answered by vrogopalapeta222
2

Answer:

given that

no.of revolution = 20

time = 10 second

2×3.14×2=12.57

Answered by VineetaGara
2

Given,

Number of revolutions made by a stone in 10 seconds, moving along a circular path = 20

To find,

The angular velocity of the stone.

Solution,

We can simply solve this numerical problem by using the following process:

Mathematically,

Angular velocity (omega)= 2π × frequency of revolutions (f)

And, frequency of revolutions (f)= total number of revolutions/time taken {Equation-1}

Now, according to the question;

Frequency of revolutions of the stone (f)

= total number of revolutions/time taken

(according to equation-1)

= 20 rev/10 s = 2 rev/s

Now,

The angular velocity of the stone

= 2π × frequency of revolutions (f)

(according to equation-1)

= 2 × 3.14 × 2 s^-1

= 12.56 s^-1

Hence, the angular velocity of the stone is equal to 12.56 s^-1.

Similar questions