A stone moving along a circular path moves 20 revolutions in 10 seconds.what is the angular velocity of the stone?
Answers
Answer:
given that
no.of revolution = 20
time = 10 second
2×3.14×2=12.57
Given,
Number of revolutions made by a stone in 10 seconds, moving along a circular path = 20
To find,
The angular velocity of the stone.
Solution,
We can simply solve this numerical problem by using the following process:
Mathematically,
Angular velocity (omega)= 2π × frequency of revolutions (f)
And, frequency of revolutions (f)= total number of revolutions/time taken {Equation-1}
Now, according to the question;
Frequency of revolutions of the stone (f)
= total number of revolutions/time taken
(according to equation-1)
= 20 rev/10 s = 2 rev/s
Now,
The angular velocity of the stone
= 2π × frequency of revolutions (f)
(according to equation-1)
= 2 × 3.14 × 2 s^-1
= 12.56 s^-1
Hence, the angular velocity of the stone is equal to 12.56 s^-1.