a stone of 1 kg is trown with a velocity 20 m/s across the frozen surface of a lake come to rest after travelling a distance of 50 M what is the force of friction between the stone and ice
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2as = v² - u²
2a(50) = 0 - (20)²
a = -400/100
a = -4m/s²
Fricition = ma = 1 * (-4) = -5N
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