Question

A stone of 80 g attached tied with a string whirls in a horizon radius 1 m. What will be the speed of the stone if the​

Answer 1

Here, r=80cm=0.8,v=14/25s−1. :.ω=2π=2×227×1425=8825rad.S−10.

The centripetal acceleration , a=ω2r=(8825)2×0.80=9.90ms−2

The direction of centripetal acceleration is along the string directed towards the centre of circular path.

Answer 2

Answer:

Frequency f= 25/14 Hz

Angular velocity ω=2πf= 2×14π/25 rad/s=3.52rad/s

Acceleration is a=ω^2r=3.52^2×0.8=9.9m/s

The direction is along the radius at every point towards the centre.