a stone of density 3000 kg/m3 is lying submerged in water of density 1000kg/m3 if the mass of the stone in air is 150 kg calculate the force required to lift the stone
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density of stone =3000 kg m3
density of water= 1000 kg m3
mass of stone = 150 kg
volume of stone = 150 ÷ 3000= 0.05m3
force= 0.05×1000×10=0.05×10³×1=0.05×10⁴
force= 500N
density of water= 1000 kg m3
mass of stone = 150 kg
volume of stone = 150 ÷ 3000= 0.05m3
force= 0.05×1000×10=0.05×10³×1=0.05×10⁴
force= 500N
srj11:
no I am sorry this is not a right answer. i wants to know the steps. but the answer is 1000N
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