A stone of density 3000 kg/m3 is lying submerged in water of density 1000kg/m3 if the mass of the stone in air is 150 kg calculate the force required to lift the stone
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Volume of the stone, v=1503000=0.05 m3
Weight of the water displaced by the stone=0.05×1000×g=0.05×1000×10=500 N
Buoyancy force =500 N
Wight of the stone =150×g=150×10=1500 N
The force needed to lift the stone =(1500−500) N=1000 N
Weight of the water displaced by the stone=0.05×1000×g=0.05×1000×10=500 N
Buoyancy force =500 N
Wight of the stone =150×g=150×10=1500 N
The force needed to lift the stone =(1500−500) N=1000 N
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