Physics, asked by kollipara7409, 11 months ago

A stone of man 10kg is thrown vertically upward with velocity 40m/s find the potential energy and kinetic energy after 2sec

Answers

Answered by meezan0571
0

after 2 sec, height would become 60 m {by using s=ut+1/2 at*t formula} so P.E becomes mgh = 10*10*60= 6000 J

.

vel after 2 seconds is = 40-(10*2)= 20 m/sec hence K.E = 1/2 * m * v * v = 2000 J

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