Question

A stone of mass 0
.08kg is whirled bye a string in a horizontal circle of radius 0.5m completing 60rpm . Find the momentum and centripetal froce

Answer 1

Answer:

Momentum=0.25, Centripetal force =0.19N

Explanation:

Omega(w) =2pi*60/60

= 2pi

=6.28 rad

V=wr

V=6.28*0.5

V=3.14m/s

Momentum =mv

=0.08*3.14

=0.25

Centripetal force =mv^2/r

=0.08/2*(3.14)^2

=0.19

I hope the answer will help you mate

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