A stone of mass 0.1 kg is thrown vertically upwards. Give the magnitude and direction of the net force on the stone (a) during its upward motion (b) during its downward motion (c) at the highest point where it momentarily comes to rest.
Answers
Answered by
39
Hii dear,
# Answer- 1 N everywhere.
# Explaination-
a) In all three cases i.e. upwards, downwards and at highest point the only force acting on stone is gravitational force.
At any point, acceleration due to gravity always acts downwards with magnitude g = 9.8 m/s^2.
Gravitational force is given by,
F = ma = mg
F = 0.1×10
F = 1 N.
Hence, force of 1 N in downwards direction will act on stone in all 3 conditions.
Hope that is useful.
# Answer- 1 N everywhere.
# Explaination-
a) In all three cases i.e. upwards, downwards and at highest point the only force acting on stone is gravitational force.
At any point, acceleration due to gravity always acts downwards with magnitude g = 9.8 m/s^2.
Gravitational force is given by,
F = ma = mg
F = 0.1×10
F = 1 N.
Hence, force of 1 N in downwards direction will act on stone in all 3 conditions.
Hope that is useful.
Answered by
0
Answer:
0.98N
Explanation:
a) F=mg
F=0.1×9.8
=0.98N
in b) nd c) is also 0.98N cauz only gravitational force is acting on it
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