Question

A stone of mass 0.12 kg is fired from a catapult. The velocity of the stone changes from 0 to 5.0 m / s in 0.60 s. What is the average resultant force acting on the stone while it is being fired?

Answer 1

Answer:

1 Newton

Explanation:

f=m(v-u)/t

f=?

m=0.12kg

u=0m/s

v=5m/s

t=0.6 seconds

f= 0.12(5-0)/0.6

f= 0.6/0.6

f=1 Newton

1 Newton is the force