Question

a stone of mass 0.5 kg is attached to a string of length 2 metre and is held in a horizontal circle if the string can with stand a tension of 9 and the maximum velocity with which the stone can whirled​

Answer 1

Answer:

Explanation:

Maximum tension of the string = maximum centripetal force experienced by the stone

=> mv2/r = 25

=> 2v2/3 = 25

=> 2v2 = 75

=> v2 = 37.5

=> v = 6.123 m/s