Physics, asked by manish8098, 4 months ago

A stone of mass 0.5 kg is attached to a string of length 2 m and is whirled in a horizontal circle. If the string can with stand a tension of 9N, the maximum velocity with which the stone can be whirled is ?

Answers

Answered by Anonymous
93

 \: {\Large{\rm{Given  }}}\: :\: \\  \\   \:  \:  \:  \:  \: \bullet \rm \: Mass   \: (M) \: = \:  0.5 \: kg \\\\ \:  \:  \:  \:  \:  \bullet \rm \:Radius  \: (R) \: =  \: 2 \: m \\\\ \:  \:  \:  \:  \: \bullet \rm \:  Tension \: (T) \: = \: 9N \:  \\  \\{\Large{\rm{To\:Find  }}}\: :\\  \\ \:  \:  \:  \:  \: \bullet \rm \: Velocity_{(max)}\:which \:  the  \: stone \:  can \:  be  \: whirled \\  \\ {\Large{\rm{Solution }}}\: :  \\ \\   \rm Centrifugal \:  force \:  = \:  tension  \: in \:  string\  \\    \\ \rm \: \frac{MV  ^{2}}{r} = T \: \\  \\  \:\  \:  \: \longrightarrow \: \rm  \: V \:  =  \:  \sqrt{ \frac{Tr}{M} } \:  \\   \\ \:  \:  \:  \: \longrightarrow \: \rm  \: V \:  =  \:  \sqrt{ \frac{9 \times 2}{0.5}} \: \\\\  \:  \:  \:  \: \longrightarrow\:\rm   \: V \: = \: 6 \: ms {}^{ - 1}  \\  \\ \therefore \:\rm  Maximum  \: velocity  \: of \:  stone  \: is \: 6 \: ms {}^{ - 1}  \:

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