Question

a stone of mass
0.5 kg is released from top of a tower height 200 m what is its kinetic energy?​

Answer 1

According to law of conservation of energy kinetic energy of the rock before hitting the ground will equal to the potential energy of the rock.

• Mass=m=0.5kg
• Height=h=200m
• Acceleration due to gravity=g=10m/s^2

We know

$\boxed{\sf P.E=mgh}$

$\\ \sf\longmapsto P.E=0.5(10)(20)$

$\\ \sf\longmapsto P.E=5(200)$

$\\ \sf\longmapsto P.E=1000J$

Answer 2

Answer:

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Explanation:

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