a stone of mass 0.5 kg is tied to one end of string of 1.5 M length if the stone is whirled in a vertical circle of radius 2 m about the other and at the constant speed of 5 metre per second the tension in the string at the lowest point is
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The centripetal force for the stone is equal to the tension T in the string
T= mv^2\r
= 0.5×4^2\1
=8N
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