Question

A stone of mass 0.5 kg with a velocity of 40 m/s . How much is K.E . of the stone is at the time it strikes the ground .
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Answer 1

Answer:

400J

Explanation:

K.E = 1

---- × mass × velocity^2

2

= 1 × 0.5 × (40)^2

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2

= 1 × 0.5 × 1600

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2

= 0.5 × 800

= 400 J