Question

A stone of mass 0.5kg is attached to a string of length 2m and is whirled in a horizantalcircle if the string can withstand High Tension of 9 Newtons the maximum velocity with which the stone can be whirled is

Answer 1

Tension developed in the string is equal to the centripetal force acting away from the centre of the circular path.

Centrefugal force =
$m \frac{ {v}^{2} }{r}$
Therefore,T=
$m \frac{ {v}^{2} }{r}$
Given T=9N

$m \frac{ {v}^{2} }{r} =9$
${v}^{2} = \frac{9 \times 2}{0.5}$
$v = \sqrt{36}$
v=6m/s

Answer 2

Answer:

6m/s

Explanation:

THEREFORE YOUR ANSWER IS 6m/s.

I hope you are satisfied by my answer.