Question

A stone of mass 0.6kg attached to a string of length 0.5m is whirled in a horizontal circle at a constant
speed. If the maximum tension in the string is 5N before it breaks, calculate:
a) The maximum speed of the stone
b) The maximum number of revolutions per second it can make

Answer 1

a) The maximum speed of the stone

V=(r FC/m)1/2

=(0.5*5/0.6)1/2

= 5m/s.

b) The maximum number of revolutions per second it can make

f=?/2p

=v/2pr

= 5/2p*0.5

=1.593Hz.

$ItzDopeGirl$❣

Answer 2

Answer:

A)The maximum speed of the stone

V=(r FC/m)1/2 =(0.5*5/0.6)1/2 = 5m/s.

b) The maximum number of revolutions per second it can make

f=?/2p =v/2pr

= 5/2p*0.5 =1.593Hz.

Explanation: