A stone of mass 1 kg is tied to the end of a string of 1m length. it is whirled in a vertical circle. if the velocity of the stone at the top be 4m/s. what is the tension in the string
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centripetal force will be given by
F=ma
=m(v^2/r)
=1×(4^2/1)
=16
this force will be balanced by tension in the string..
so tension will be 16 N
F=ma
=m(v^2/r)
=1×(4^2/1)
=16
this force will be balanced by tension in the string..
so tension will be 16 N
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