A STONE OF MASS 1 KG TIED TO A LIGHT INEXTENSIBLE STRING OF LENGTH L = 10/3 m WHIRLING IN A CIRCULAR PATH IN A VERTICAL PLANE THE RATIO OF MAXIMUM TENSION IN THE STRING TO THE MINIMUM TENSION IN THE STRING IS 4 IF g IS TAKEN TO BE 10 m/sec2 , the speed of the ston at the highest point of the circle is ;
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" Ratio of maximum tension is T2=4T
Different of two tensions will be 6 mg
T1= 2mg
Now tension at the top of right circle is
T1+ Mv21/r
V1=√10g
=√10x10
=10m/s
Hence the student can solve with the given formula to find out the value of the V in fine manner without meeting risk of it.
"
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