Question

a stone of mass 10 gram is being moved in a circle of radius 50 cm with a uniform speed of 1 metre per second the acceleration of the stone ?

Answer 1

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♦ Centripetal Acceleration ♦  

→ Defining F = ( Centripetal Force ) | "m", "a" holding their usual meaning
→ 'v' is the Tangential Velocity | 'r' is the Radius of the system
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◘ Solution :
 
  • 'r' = 50cm = 0.5 m 
  • 'v' = 1m s⁻¹

→ F = ma = mv² r ⁻¹
  => a = v² r ⁻¹

→ Centripetal Acceleration = ( 1 )² / ( 0.5 ) = 2m s⁻²
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► For any further reference :
 → https://study.com/academy/lesson/centripetal-force-definition-formula-examples.html 
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☺ Hope it helps 

Answer 2

The acceleration of the stone is 2 m/s^2 .

• Acceleration was due to the circular motion of the stone , known as centripetal acceleration.
• Centripetal acceleration = (velocity * velocity) / (radius of the circle)
• According to the question,

         speed = 1 meter per second

         radius of the circle = 50 cm = 0.5 m

    Then, centripetal acceleration of the stone

                       =  (1 * 1) / 0.5

                       = 2 m/s^2