Question

A stone of mass 100 kg breaks into two parts such that momentums of the parts are equal and opposite. If the first part of mass 60 kg moves towards north with velocity 20 ms? What is the velocity of the second part?
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Answer 1

Answer:

Given m = 1.5m

r = 1.5 m

w = 40 rpm = 40×2π60 rad/s

= 43π rad/s

Now Tension T = mrw²

= 0.25 × 1.5 × (43π)2

= 0.58 N

Tmax = 200 N

Tmax = mv2(max)r

⇒ Vmax = 200×1.50.25−−−−−−√ = 34.6 m/s.

Explanation:

put questions value

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