Question

a stone of mass 100gm is tiend to a string of length 500 cm and is revolve in a horizontal circle of its make 120 rpm calculated 1-frequency 2- Time period 3- angular speed 4- linear speed 5- centripetal acceleration 6- centripetal force 7- Breaking tension 8- K .e of rotating body in physics class 11th​

Answer 1

m=100g

=0.1kg,

r=50cm = 0.5m,

g=9.8m/s²,

$v_{L}$ =7m/s

To find : Velocity at the highest point $v_{H}$

$v_{H}$ = $\sqrt{\frac{2(TE_{H})}{m} - 4gr}$

Calculation : Total energy at highest point,

T.E (H )=K.E at lowest point = $\frac{1}{2} mv^{2} _{L}$

∴T.$E_{H}$= $\frac{1}{2}$ x 0.1 x 7²

=2.45J

From formula,

$v_{H} = \sqrt{\frac{2(2.45)}{0.1} - 4 * 9.8 * 0.5}$

     = $\sqrt{29.4} = 5.422m/s$

The velocity at the highest point is 5.422m/s

Hope it is helpful

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