Question

a stone of mass 100kg is dropped from the top of the tower it takes 2s to reach the ground calculate the height of the tower​

Answer 1

Answer:

Given, a=g=10m/s2

t=2s

u=0m/s        {Initial velocity at rest}

So, height= ut+1/2at^2

=(0)(u)+1/2(10)(4)

=20m

∴ Height of the tower= 20m