Question

A stone of mass 1kg is dropped from a height of 500m. What will be it’s velocity when it will touch the ground

Answer 1

Answer:

HEY

Explanation:

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Answer 2

Answer:-

100m/s

Explanation:-

Given :

• Initial velocity, u = 0m/s

• Mass, m = 1kg

• Height, s = 500m

• Acceleration, a=10m/s^2

To Find

Final velocity, v = ?

Formula to be use :

$\bullet\ \sf{} v^{2}-u^{2}=2as$

Solution :

Put value in the above formula

$\sf{}v^{2}-0^{2}=2(10)(500)$

$\Rightarrow \sf{}v^{2}}= 0^{2}+ 10000$

$\Rightarrow \sf{}v^{2}}= 0+ 10000$

$\Rightarrow \sf{}\sqrt{(v})^{2}}=\sqrt{ 10000}$

$\Rightarrow \sf{}v = 100m/s$

Therfore,it’s velocity is 100m/s