Question

A stone of mass 1kg is thrown vertically upward and it need to reach 6seconds to reach the maximum height. Find out the initial velocity with which it is thrown upward. Please fast do this question

Answer 1

The stone is thrown upward and it reaches its maximum height, so

Initial velocity u = we need to find

Final velocity v = 0, as the stone comes to rest at highest point

Time taken to reach max height = 6 s

Using our formula v = u - gt

where g = acceleration due to gravity

0 = u - (9.8)(6)  [ g = 9.8 ]

0 = u - 58.8

u = 58.8 m/s

Therefore initial velocity is 58.8 m/s

Answer 2

Hello Dear.

Given ⇒

Mass of the Body = 1 kg.
Time taken by the Body to reach the Height = 6 seconds.

Let the Initial Velocity of the Ball be 0.
Acceleration of the Ball = -g = -  10 m/s².

[Since, the Ball is going against the Gravity]

Final Velocity(v) = 0

Now,
Using the Equation of the Motion,

v - u = gt
0 - u = ( 10)(6)
- u =-60 m/s.
⇒ u = 60 m/s.

∴ Initial Velocity of the Stone is 60 m/s.


Hope it helps.